0=(-0.3x^2)+24x

Solution for 0=(-0.3x^2)+24x equation:

0=(-0.3x^2)+24x

We move all terms to the left:

0-((-0.3x^2)+24x)=0

We add all the numbers together, and all the variables

-((-0.3x^2)+24x)=0


We calculate terms in parentheses: -((-0.3x^2)+24x), so:

(-0.3x^2)+24x

We get rid of parentheses

-0.3x^2+24x

Back to the equation:

-(-0.3x^2+24x)


We get rid of parentheses

0.3x^2-24x=0

a = 0.3; b = -24; c = 0;
Δ = b2-4ac
Δ = -242-4·0.3·0
Δ = 576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{576}=24$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-24)-24}{2*0.3}=\frac{0}{0.6}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-24)+24}{2*0.3}=\frac{48}{0.6}
=80
$